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To make a fair comparison, the prices were calculated for 1.5 gallons of usable epoxy mixture even though some epoxies do not sell that way or the mix ratio is different than 2:1. Prices per 1.5gal ( 3.785 L)

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1. Sulphur dioxide and oxygen were mixed in a 2:1 mol ratio and sealed in a flask with a catalyst. The following equilibrium was established at temperature T The partial pressure of sulphur dioxide in the equilibrium mixture was 24 kPa and the total pressure in the flask was 104 kPa.

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The LED set with the 476-nm blue emitter will require a 2.1:4.3:1.0 RGB mixing ratio but simply changing to a 465-nm emitter shifts it to 4.1:10.6:1. From these results, it is apparent that if the standard 3:6:1 mixing ratio were applied to most LED sources, the color they produced would be noticeably different from the D65 broadcast standard ...

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Select a dilution Ratio, Enter a Container Volume Size and Click Calculate. Ratio: 1:5 1:8 1:10 1:15 1:20 1:24 1:30 1:40 1:50 1:60 1:80 1:100 1:120 1:150 1:200 1:300 Container Volume: Litres Millilitres

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The oxygen-fuel mass ratio is then: 2 * 32 / 1 * 16.042 = 64 / 16.042. So we need 3.99 kg of oxygen for every 1 kg of fuel. Since 23.2 mass-percent of air is actually oxygen, we need : 3.99 * 100/23.2 = 17.2 kg air for every 1 kg of methane. So the stoichiometric air-fuel ratio of methane is 17.2.

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Ethanol Water mixtures. Hi! I believe there is a typo in the ethanol-water mixtures table. The vol% value for density = 0.90418 is written as 52.9, but I believe it was meant to be 62.9.

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To make a fair comparison, the prices were calculated for 1.5 gallons of usable epoxy mixture even though some epoxies do not sell that way or the mix ratio is different than 2:1. Prices per 1.5gal ( 3.785 L)

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A ratio is in its simplest form when both sides are whole numbers and there is no whole number that both sides can be divided by. In the fruit drink example above, 2:6 was the original ratio given, but 1:3 is the simplest form of the ratio.

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1. The equilibrium equation for the formation of ammonia is: N 2(g) + 3H 2(g) 2NH 3(g) In an equilibrium mixture at 200 °C, the concentrations were found to be as follows: [N 2] = 2.12M, [H 2] = 1.75M and [NH 3] = 84.3M Notice the 3 sd’s in all your data. Calculate the value of the Equilibrium Constant for this reaction at 200°C.

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Don't let the math scare you anymore! This video shows a quick and easy way to calculate the ratios associated with mixing two-part resin systems like...

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Using the Ratio Calculator. Resort to the help of this amazing ratio calculator when you have you settle ratio/proportion problems and check equivalent fractions. Despite the fact that you cannot enter a ratio of 4/5 into this calculator, it accepts values such as 4:5, for example, 4/3 should be written as 4:3.

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